(n-2)(n+2)=n^2

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Solution for (n-2)(n+2)=n^2 equation: 



(n-2)(n+2)=n^2

We move all terms to the left:

(n-2)(n+2)-(n^2)=0

determiningTheFunctionDomain
-n^2+(n-2)(n+2)=0

We add all the numbers together, and all the variables

-1n^2+(n-2)(n+2)=0

We use the square of the difference formula

-1n^2+n^2-4=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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